Evaluate using suitable identities: (999)^{3} | vedclass

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Question

(B) We can express $999$ as $(1000 - 1)$.Using the algebraic identity $(x - y)^{3} = x^{3} - y^{3} - 3xy(x - y)$,where $x = 1000$ and $y = 1$:$(1000 -

Vedclass · Accepted Answer

$997002999$

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(B) We can express $999$ as $(1000 - 1)$.Using the algebraic identity $(x - y)^{3} = x^{3} - y^{3} - 3xy(x - y)$,where $x = 1000$ and $y = 1$:$(1000 - 1)^{3} = (1000)^{3} - (1)^{3} - 3(1000)(1)(1000 - 1)$$= 1,000,000,000 - 1 - 3000(999)$$= 1,000,000,000 - 1 - 2,997,000$$= 1,000,000,000 - 2,997,001$$= 997,002,999$

Evaluate using suitable identities: $(999)^{3}$

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